2S + 302 = 2SO3
Mass of S = 6.3g
Mass of 02 = 10.0g
n = m/M
M(S) = 32g/mol
n = 6.3g/32g/mol
n = 0.195mol
n(S)/n(SO3) = 2/2
Let n(SO3) = x
2(0.195) = 2x
0.39 = 2x
x = 0.195
Therefore, n(SO3) = 0.195mol
For mass of SO3
m = M×n
But M(SO3) = (32×1) + (16×3)
= 80g/mol
m = 80g/mol × 0.195mol
m = 15.6g
Therefore, 15.6g of SO3 will be produced.
HOPE IT HELPS. HAVE A WONDERFUL DAY.