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Find f(x) if f'(x)=x²+3x-4

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Answer:


f(x)=(1)/(3)x^3+(3)/(2)x^2+4x+C

Explanation:


f'(x)=x^2+3x+4\\\int f'(x)\,dx=\int (x^2+3x+4)\,dx\\f(x)=(1)/(3)x^3+(3)/(2)x^2+4x+C

User Josh Hardman
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