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How many gallons of a 90% antifreeze solution must be mixed with 100 gallons of 25% antifreeze to get a mixture that

is 80% antifreeze? Use the six-step method.
You need gallons.
(Round to the Question Viewer ber.)
answer

User Jcoke
by
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1 Answer

7 votes

Answer:

550 gallons

Explanation:

Let
x be the number of gallons for the 90% antifreeze solution and
x+100 be the total number of gallons that will contain 80% antifreeze solution:


\displaystyle (0.90x+0.25(100))/(x+100)=0.80\\\\0.90x+25=0.80x+80\\\\0.10x+25=80\\\\0.10x=55\\\\x=550

Therefore, you would need 550 gallons of the 90% antifreeze solution.

User Mantu
by
7.7k points