34.9k views
0 votes
Passing through (-4,1) and parallel to the line whose equation is 5x-2y-3=0

User RichieHH
by
7.5k points

1 Answer

5 votes

Answer:


y=(5)/(2)x+11

Explanation:

Convert to slope-intercept form


5x-2y-3=0\\5x-3=2y\\y=(5)/(2)x-(3)/(2)

Since the line that passes through (-4,1) must be parallel to the above function, then the slope of that function must also be 5/2:


y-y_1=m(x-x_1)\\y-1=(5)/(2)(x-(-4))\\y-1=(5)/(2)(x+4)\\y-1=(5)/(2)x+10\\y=(5)/(2)x+11

Therefore, the line
y=(5)/(2)x+11 passes through (-4,1) and is parallel to the line whose equation is
5x-2y-3=0. I've attached a graph of both lines if it helps you better understand!

Passing through (-4,1) and parallel to the line whose equation is 5x-2y-3=0-example-1
User Jeffrey Lott
by
8.2k points

No related questions found