233k views
5 votes
Question #3

Solve for x
10
6x + 8
K
U
N
L
122°
M
194°

Question #3 Solve for x 10 6x + 8 K U N L 122° M 194°-example-1

2 Answers

5 votes

Answer:

be more clear of what u mean edit the question and explain more of u mean

User Vikrant Bhat
by
8.4k points
7 votes

Answer:

(b) 7

Explanation:

You want to find the value of x in the figure where chords that cross at an angle of 122° intercept arcs of 195° and (6x+8)°.

Crossing angle

The angle where the chords cross is half the sum of the measures of the intercepted arcs:

(194° +(6x +8)°)/2 = 122°

101 +3x = 122 . . . . . . . . . . divide by °, simplify

3x = 21 . . . . . . . . . . . subtract 101

x = 7 . . . . . . . . . . divide by 3

The value of x is 7.

__

Additional comment

The measure of arc KU is 50°.

<95141404393>

User Artiom Chilaru
by
7.7k points

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