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Question 5(Multiple Choice Worth 1 points)

(01.07 MC)

Lines BC and ED are parallel. They are intersected by transversal AE, in which point B lies between points and E. They are also intersected by transversal EC. Angle ABC measures 70 degrees. Angle CED measures 30 degrees.

Given: line BC is parallel to line ED
m∠ABC = 70°
m∠CED = 30°

Prove:m∠BEC = 40°

Statement Justification
line BC is parallel to line ED Given
m∠ABC = 70° Given
m∠CED = 30° Given
m∠ABC = m∠BED Corresponding Angles Theorem

m∠BEC + 30° = 70° Substitution Property of Equality
m∠BEC = 40° Subtraction Property of Equality


Which of the following accurately completes the missing statement and justification of the two-column proof?

m∠BEC + m∠CED = m∠BED; Definition of a Linear Pair
m∠ABC + m∠BEC = m∠BED; Angle Addition Postulate
m∠ABC + m∠BEC = m∠BED; Definition of a Linear Pair
m∠BEC + m∠CED = m∠BED; Angle Addition Postulate

Question 5(Multiple Choice Worth 1 points) (01.07 MC) Lines BC and ED are parallel-example-1
User Jhilom
by
8.4k points

1 Answer

5 votes

Answer:

m∠BEC + m∠CED = m∠BED; Angle Addition Postulate

Explanation:

You need to show that <BED is made up of angles BEC and CED by the Angle Addition Postulate.

m∠BEC + m∠CED = m∠BED; Angle Addition Postulate

User Arun Raja
by
7.5k points
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