Answer:
94.5kJ
Step-by-step explanation:
To calculate the energy released by the thermal energy store associated with the water cooling, we can use the following formula:
Q = mcΔT
where Q is the energy released, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature.
We first need to calculate the temperature change of the water. The initial temperature of the water is the boiling point of 100°C, and the final temperature is the room temperature of 25°C. Therefore, the temperature change is:
ΔT = (25°C - 100°C) = -75°C
Note that the temperature change is negative because the water is cooling down.
Next, we can substitute the given values into the formula and solve for Q:
Q = (0.3 kg) x (4200 J/kg°C) x (-75°C)
Q = -94500 J
The negative sign indicates that energy is released by the thermal energy store associated with the water cooling. Therefore, the energy released is 94,500 J, or approximately 94.5 kJ.