Answer:
we can use combinatorics to solve this problem. We want to find out how many possible outcomes there are from rolling a die 5 times and having only 2 rolls land on 6.
One way to approach this is to note that we have 3 rolls that cannot be 6 and 2 rolls that must be 6. The number of ways to choose which 2 rolls are 6 is given by the binomial coefficient (5 choose 2), which is 10.
For the remaining 3 rolls that cannot be 6, each roll has 5 possible outcomes (since there are 6 possible outcomes for each roll, but we cannot have a 6 for those rolls). So the total number of possible outcomes is:
10 * 5 * 5 * 5 = 1250
Therefore, there are 1250 possible outputs from rolling a die 5 times and having only 2 rolls land on 6.
Step-by-step explanation: