Answer:
The answer is option b. ([],(PO).(P1).(P3).(PO.P1).(PO, P3).(P1, P3).(PO, P1, P3)). This is a valid partitioning of the set P into 7 disjoint subsets, including the empty set and the set P itself. Each of the subsets is non-empty and their union is equal to P.
Step-by-step explanation: