Question

A 1000 kg motor vehicle starts from an initial velocity 1 m/s and after traveling at a distance of 113 m on a straight-line path, its speed is found to be 28 m/s. What is the magnitude of the average net acceleration of the car during the travel on this straight-line path? No need to write the unit. Please write the answer in one decimal place. (eg 1.234 should be written as 1.2).

Answer 1

The acceleration is 3.5.

Step-by-step explanation:

According to the question, the initial velocity is given as 1 m/s, the distance travelled is given as 113 m and the final velocity is given as 28 m/s.

Observe equation 1,
`v^(2) = u^(2) +2a s` where v is the final velocity, u is the initial velocity, a is the acceleration and s is the distance. Rearranging for acceleration gives

`a = (v^(2) -u^(2) )/(2s)`

Thus,
`a = (28^(2)-1^(2) )/(226)`

Therefore, acceleration is 3.4646 which is 3.5 to 1 decimal place.