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3 votes
INT [ ] a = new int [10];

int i, j;
for (j = 0; j < 9; j++) {
a[ j ] = 0;
}
a [ j ] = 1;
for ( i = 0; i < 10; i++) {
system.out.println ( i + " " + a[ i ] );
}
* Please explain step by step how did you get to the solution as i'm confused

1 Answer

3 votes

Let's go through the code step by step to understand what it does:

1. `int[] a = new int[10];`

  • - This line declares an array named `a` of type `int` with a length of 10. This means that `a` can store 10 integers.

2. `int i, j;`

  • - This line declares two integer variables `i` and `j` without initializing them.

3. `for (j = 0; j < 9; j++) { a[j] = 0; }`

  • - This `for` loop initializes elements 0 to 8 of the array `a` to the value 0. It starts with `j` equal to 0 and increments `j` by 1 until `j` is no longer less than 9.

4. `a[j] = 1;`

  • - After the previous `for` loop, `j` is equal to 9. This line assigns the value 1 to the element at index 9 of the array `a`. So, the last element of the array is set to 1.

5. `for (i = 0; i < 10; i++) { System.out.println(i + " " + a[i]); }`

  • - This `for` loop iterates from `i` equal to 0 to `i` less than 10. Inside the loop, it prints the value of `i` concatenated with a space, followed by the value of `a[i]`.
  • - The output of this loop will be:

```

0 0

1 0

2 0

3 0

4 0

5 0

6 0

7 0

8 0

9 1

```

So, the final output will display the numbers from 0 to 9 along with the corresponding values stored in the array `a`. All elements except the last one will have the value 0, and the last element will have the value 1.


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