Hello!
a 120-v power supple connected to a 10-ohm resistor will produce 3.464 amps of current
P = 120 V
r = 10Ω
P = r * I²
I² = P ÷ r
I² = 120 ÷ 10
I² = 12
I = √12
I ≈ 3.464
9.5m questions
12.2m answers