Question

B. Determine the volume fraction of pores in silica gel filled with adsorbed water vapor when its partial pressure is 4.6mmHg and the temperature is 250 ∘

C. At these conditions, the partial pressure is considerably below the vapor pressure of 23.75mmHg. C. In addition, determine whether the amount of water adsorbed is equivalent to more than a monolayer, if the area of an adsorbed water molecule is given by the equation below and the specific surface area of the silica gel is 830 m 2
/g,ε p
​
=0.47,rho p
​
=1.09 g/cm 3
and its capacity for water vapor at 25 0
C= 0.0991 g adsorbed water/ g silica gel =A C
​
=1.091(M/N A
​
rho L
​
) 2/3
- N A
​
=6.023×10 23
molecules / mole

Answer 1

To determine the volume fraction of pores in silica gel filled with adsorbed water vapor, calculate the density of water vapor and compare it to the specific surface area.

Step-by-step explanation:

First, let's calculate the density of water vapor that creates a partial pressure equal to the vapor pressure. We can use the ideal gas law: PV = nRT. Rearrange the formula to solve for density, which is mass/volume. Substitute the values and calculate the density in g/m³.

To determine whether the amount of water adsorbed is equivalent to more than a monolayer, we need to compare it to the specific surface area of the silica gel. Use the given equation and plug in the values to find the amount of water adsorbed. If it exceeds the specific surface area, then it is more than a monolayer.