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which of the following are solutions to the quadratic equation check all that apply x ^ 2 + 10x + 25 = 2

User Jgran
by
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1 Answer

3 votes

Answer:

to solve the equation you first need to bring it to factors and by doing that you first need to let the equation equal 0 hence you need to minus 2 on both sides of the equation therefore

x^2 + 10x + 25 - 2 =2 - 2

therefore

x^2 + 10x +23 = 0

now since the equation cannot be factored, we use the formula.

x=
\frac{-b +- \sqrt{b^(2)-4ac } }{2a}

where

a=1

b=10

c=23

note we use the coefficients only.

therefore x =
\frac{-10 -+ \sqrt{10^(2)-4(1)(23) } }{2(1)}

=
(-10-+√(100-92) )/(2)

=
(-10-+√(8) )/(2)

then we form two equations according to negative and positive symbols

x=
(-10+√(8) )/(2) or x =(-10-√(8) )/(2)

therefore x =
-5+√(2) or x=
-5-√(2)

User Kevin Curnow
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