Answer:
1/6
Explanation:
Total sum if the first roll is 1:
1 + 1 = 2
1 + 2 = 3
1 + 3 = 4
1 + 4 = 5
1 + 5 = 6
1 + 6 = 7
Total sum if the first roll is 2:
2 + 1 = 3
2 + 2 = 4
2 + 3 = 5
2 + 4 = 6
2 + 5 = 7
2 + 6 = 8
Total sum if the first roll is 3:
3 + 1 = 4
3 + 2 = 5
3 + 3 = 6
3 + 4 = 7
3 + 5 = 8
3 + 6 = 9
Total sum if the first roll if 4:
4 + 1 = 5
4 + 2 = 6
4 + 3 = 7
4 + 4 = 8
4 + 5 = 9
4 + 6 = 10
Total sum if the first roll is 5:
5 + 1 = 6
5 + 2 = 7
5 + 3 = 8
5 + 4 = 9
5 + 5 = 10
5 + 6 = 11
Total sum if the first roll is 6:
6 + 1 = 7
6 + 2 = 8
6 + 3 = 9
6 + 4 = 10
6 + 5 = 11
6 + 6 = 12
If we look at all the possible rolls we get from two dice, we see that there are 36 different possibilities. Out of all of these, only 6 rolls produce a total greater than 9. [Note: I did not include the possibility of rolling a 9 or greater, but the possibility of rolling greater than 9.] So, the possibility of rolling two dice and getting a sum greater than 9 is 6/36, or 1/6.
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