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The intensity of a certain sound wave is 6 W/cm 2. If its intensity is raised by 10 decibels, the new intensity is: O A. 600 µW/cm² OB. 6.06 W/cm² O C. 12 µW/cm² O D. 6.6 W/cm2 O E. 60 µW/cm² Question 33 The potential energy for the interaction between the two atoms in a diatomic molecule is U = A/ x 12 - B/ x6, where A and B are constants and x is the interatomic distance. The magnitude of the force that one atom exerts on the other is: P F F OA. 72A/x12-72B/x6 O B.-11A/x11 + 5B/x5 OC. A/x13 - B/x7 OD. 12A/X13-6B/X7 O E.-13A/x13 + 7B/x7

User Farzad J
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Final answer:

The new intensity of the sound wave is 60 W/cm²

Step-by-step explanation:

The intensity of a sound wave is a measure of the power carried by the wave per unit area. It is given by the formula I = P/A, where I is the intensity, P is the power, and A is the area.

If the initial intensity is 6 W/cm² and it is raised by 10 decibels, we can use the formula:

I2 = I1 * 10^(dB/10)

Substituting the given values, we have: I2 = 6 * 10^(10/10) = 60 W/cm².

User Vinodh
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