Question

Arrange this isoelectronic series in order of decreasing radius: F-02-, Mg2+ , Na+ .

Answer 1

Mg2+ < Na+ <F−< O2−

Step-by-step explanation:

For isoelectronic species, ionic radii decrease with an increase in nuclear charge (i.e., no. of protons). Thus, for isoelectronic species, the cation with the greater +ve charge will have a smaller radius and the anion with greater -ve charge will have a larger radius.

thus, the answer is Mg2+ < Na+ <F−< O2−