Question

An object moves along x-axis according to the equation ()=1-5? +5, where x in m and 1 ins, the acceleration of the object at t=1s in m/s is: O a. -8 O b. -4 O c. 2 O d. 8 O e. 14

Answer 1

The acceleration of the object at t = 1 second is -10 m/s^2, which corresponds with choice C.

Step-by-step explanation:

The high school physics question pertains to the calculation of acceleration of an object moving along the x-axis at a specific time. Given the position function x(t) = 1 - 5t^2 + 5t, we first need to determine the velocity by taking the first derivative of the position function with respect to time. The velocity function v(t) is v(t) = dx/dt = -10t + 5. Then, we find the acceleration by taking the derivative of the velocity function. This gives us a(t) = dv/dt = -10. At t = 1 s, the acceleration a(1) is -10 m/s^2.

Answer 2

The acceleration of the object at t=1s is 10 m/s².

Step-by-step explanation:

The equation describing the motion of the object is given by x(t) = 1 - 5t + 5t². To find the acceleration at t = 1s, we need to take the second derivative of the position equation. The second derivative of x(t) is the acceleration function a(t). Taking the derivative, we get a(t) = 10 m/s².