Question

Use the following information to answer the next 4 questions. Consider the following equilibrium: 2N02(g) + 2NO(g) + 02(g) Initially, 0.600 mol of NO, is placed in a 1.00 L flask. At equilibrium, the concentration of NO was found to be 0.460 mol/L. •The equilibrium law expression would be Select one:

Answer 1

Second Option ([O2]*[NO]^2)/[NO2]^2

Step-by-step explanation:

To find the Kc value of a reaction, you must divide the concentration of the products over the concentration of the reactants (divide right side of the reaction by the left side of the reaction)

you must also remember to turn the multiplier prefix such as the '2' in the 2NO into an exponent for that particular molecule in the Kc equation

as such, the second option is correct