Question

The probability of rolling a 4 on one toss of a standard six-sided die and a 6 on a second toss is: \( .334 . \) 409 \( .028 . \) \( .169 . \)

Answer 1

The probability of rolling a 4 on one toss of a standard six-sided die and a 6 on a second toss is 1/36.

Step-by-step explanation:

To find the probability of rolling a 4 on one toss of a standard six-sided die and a 6 on a second toss, we need to multiply the probabilities of each event occurring. The probability of rolling a 4 on one toss is 1/6, since there is only one favorable outcome (rolling a 4) out of six possible outcomes. The probability of rolling a 6 on the second toss is also 1/6. Therefore, the probability of both events occurring is (1/6) * (1/6) = 1/36.

Answer 2

To calculate the probability of rolling a 4 and then a 6 with a standard six-sided die, the product of individual probabilities, each being 1/6, is used, resulting in the correct probability of .0278.

Step-by-step explanation:

The question asks about the probability of rolling a 4 on one toss and a 6 on another toss of a standard six-sided die. The probability of rolling any specific number on a single die is 1/6, because there are six faces and each face has an equal chance of landing face up. Since the two tosses are independent events, the probability of both events occurring is the product of their individual probabilities.

To find the probability of rolling a 4 and then a 6, we multiply the probability of rolling a 4 (1/6) by the probability of rolling a 6 (1/6). Therefore, the calculation is (1/6) x (1/6), which equals 1/36. When converted to decimal form and rounded to four decimal places, the probability is .0278.