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(6) Find a complete set of incongruent primitive roots of \( 7 . \)

User Virtualize
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Explanation:

There should be ϕ ( ϕ ( 7 ) ) = 2 \phi(\phi(7)) = 2 ϕ(ϕ(7))=2 primitive roots modulo 7. \par Since 3 is one, the other must be 3 raised to a power relatively prime to. \par Hence, 3 and 5 are the primitive roots of modulo 7.

User Matthew Blancarte
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