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Explanation:
There should be ϕ ( ϕ ( 7 ) ) = 2 \phi(\phi(7)) = 2 ϕ(ϕ(7))=2 primitive roots modulo 7. \par Since 3 is one, the other must be 3 raised to a power relatively prime to. \par Hence, 3 and 5 are the primitive roots of modulo 7.
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