Question

Below is the S_N2 reaction between (S)-2-bromobutane and cyanide (CN^-). In the first box, draw the curved arrows to reflect electron movements. In the second box, add the organic product (the inorganic side product is already shown). In both boxes, add all lone pairs of electrons and nonzero formal charges.

Answer 1

The SN2 reaction between (S)-2-bromobutane and cyanide (CN-) involves the attack of the nucleophile (cyanide) on the electrophilic carbon atom of the bromoalkane. The organic product formed is (S)-2-cyanobutane.

Step-by-step explanation:

The SN2 reaction between (S)-2-bromobutane and cyanide (CN-) involves the attack of the nucleophile (cyanide) on the electrophilic carbon atom of the bromoalkane.

The curved arrows in the first box represent the movement of electrons during the reaction. The lone pair of electrons on the cyanide ion attacks the carbon atom of the bromoalkane, while the bromide ion leaves as a leaving group.

In the second box, the organic product is formed. The carbon atom that was previously bonded to the bromine is now bonded to the cyanide group, resulting in the formation of (S)-2-cyanobutane. The inorganic side product is already shown as NaBr.