Final Answer:
The mean (μ) of the probability distribution is 5.99, the standard deviation (σ) is approximately 7.03, and the variance (σ²) is about 49.42.
Step-by-step explanation:
To compute the mean (μ) of the probability distribution, we multiply each value of X by its respective probability P(X) and sum these products. So,
μ = (1 * 0.075) + (4 * 0.65) + (6 * 0.05) + (18 * 0.225) = 0.075 + 2.6 + 0.3 + 4.05 = 7.03.
The variance (σ²) is calculated as the sum of the squared differences between each value of X and the mean, multiplied by their respective probabilities.
σ² = (1 - 7.03)² * 0.075 + (4 - 7.03)² * 0.65 + (6 - 7.03)² * 0.05 + (18 - 7.03)² * 0.225
= 35.82.
Finally, the standard deviation (σ) is the square root of the variance:
σ = √35.82 ≈ 5.99.
These calculations demonstrate the statistical measures for this probability distribution. The mean represents the average value, indicating the expected value of X. The variance measures the spread of the distribution from the mean, while the standard deviation gives a clearer understanding of how spread out the values are around the mean. In this case, the mean (5.99), standard deviation (7.03), and variance (49.42) describe the central tendency and variability within this probability distribution.