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Show that the equation x ^ 3 + 6x - 10 = 0 has a solution between x = 1 and x = 2​

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One way to prove a solution is between two numbers is to prove that one number is negative and the other is positive. This means the graph must cross 0 between the points and thus there is a solution.

So all we have to do is plug in 1 and 2 for x and prove one is negative and the other is positive.

If we plug in 1, we get -3. If we plug in 2, we get positive 10. This means there is a solution!
Show that the equation x ^ 3 + 6x - 10 = 0 has a solution between x = 1 and x = 2​-example-1
User Will Rickards
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