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((x-3)(x^2+3x+27))/((x-9)(x+9))
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((x-3)(x^2+3x+27))/((x-9)(x+9))

User Mreferre
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1 Answer

7 votes
First I distributed everything
Then I cancelled out terms and added terms
Then I expanded the X’s and the 27 so I could cancel out the 9x
((x-3)(x^2+3x+27))/((x-9)(x+9))-example-1
User Geanine
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