Question

Rule:y is 1/3 times as large as x


HELPPPP I'm so bad at math​

Answer 1

`\left[\begin{array}{ccc}x&y\\0&0\\6&8\\12&16\end{array}\right]`

Step-by-step explanation:

The formula to this problem is:

⅓x + x = y

Using this formula we get:

1.

⅓x + x = y

⅓(0) + 0 = y

0+0=0

2.

⅓x + x = y

⅓(6) + 6= y

2 + 6 = 8

3.

⅓x + x = y

⅓(12) + 12= y

4 + 12 = 16