Question

Problem situation:

Anna is at the movie theater and has $35
to spend. She spends $9. 50
on a ticket and wants to buy some snacks. Each snack costs $3. 50. How many snacks, x
, can Anna buy?

Inequality that represents this situation:
9. 50+3. 50x≤35

Answer 1

Amount of money Possessed by Anna = $ 35

Money spent on ticket = $9.50

Money spent on Snacks = $ 3.50

Let x number of snacks, which will be least number of snacks that Anna can buy.

transforming the situation in terms of inequality

→9.50 +3.50 x≤ 35

→9.50 -9.50+3.50 x≤35-9.50

→3.50 x≤25.50

Dividing both sides by 3.50, we get

→x≤7.3(approx)

which can't be number of Snacks, as it will be an integral value.

So, minimum number of snacks with given amount of money = 7

So, Anna can buy snacks(x)={x:x≤7,x=1,2,3,4,5,6,7}=At most 7.

Explanation:

Answer 2

She can buy up to 7 snacks.

Explanation:

9.50 + 3.50 x ≤ 35

Subtract 9.5 from both sides.

3.50x ≤ 25.5

Divide both sides by 3.50

x ≤ 7.29

Since the number of snacks must be a whole number, the maximum number of snacks she can buy is the greatest whole number less than 7.29 which is 7.