Question

i do need all off them please and it can be just the choses 1,Abc..ect Given a sequence x(n) for Os n ≤ 3, where x(n)=[1 2 3 4] the sampling period and time index for a digital sample x(2) in time domain are OT=0.1 s, and time index =2 OT=0.2 s and time index = 3 OT= 0.6 s, and time index =2 Form the following difference equation y(n) = x(n) - x(n-1) +1.5y(n-2) - 0.4 y(n- 1)the transfer function H(z) is 1-2-4 a. H(z) = 1-1.5 -0.42-1 1-2-3 b. H(z) = 1-1.52-2-0.4-2 c. H(z) = 1-1.52-3+0.42-3 Oa Ob Ос difference function H(z)=(z^2+0.5z^1-0.8)/z^2 is Oy(n)=x(n)+0.5x(n-1)-0.8x(n-2) Oy(n)=x(n)+0.5x(n-2)-0.8x(n-1) Oy(n)=x(n)-0.5x(n-1)-0.8x(n-2) The following transfer functions describe digital system H(z)=(2-1)/((2-1) (z^2+z+0.5)) the stability for this system is OStable OUnstable O Marginally stable. For a given transfer function H(z)= (2+1)/(2-0.2) the impulse response h(n) is Oh(n)-1.25 8(n)+6(0.2)^n u(n) Oh(n)-1.25 8(n)-6(0.2)^n (n) Oh(n)-1.25 8(n)+6(0.2)u(n) 1 2 4 5

Answer 1

Given a sequence x(n) for Os n ≤ 3, where x(n)=[1 2 3 4] the sampling period and time index for a digital sample x(2) in time domain are OT=0.1 s.

Step-by-step explanation:

Time index =2 OT=0.2 s and time index = 3 OT= 0.6 s, and time index =2.Forming the following difference equationy (n) = x(n) - x(n-1) +1.5y(n-2) - 0.4 y(n- 1)The transfer function H(z) is 1-2-4.The answer is a).H(z) = 1-1.5 -0.4Explaination:Given sequence x(n)=[1 2 3 4].Given the sampling period and time index for a digital sample in the time domain are OT=0.1 s, and time index =2 OT=0.2 s and time index = 3 OT= 0.6 s, and time index =2.

We have to form the difference equation.y(n) = x(n) - x(n-1) +1.5y(n-2) - 0.4 y(n- 1)To find the transfer function, we have to take Z-transform and rearrange the above equation.Y(z) - z^-1Y(z) +1.5Z^-2Y(z) - 0.4Z^-1Y(z) = X(z).Transfer function H(z) = Y(z)/X(z).H(z) = (1-1.5Z^-2-0.4Z^-1)/(1-Z^-1)H(z) = 1/(1-Z^-1) - 1.5Z^-2/(1-Z^-1) - 0.4Z^-1/(1-Z^-1)H(z) = Z/(Z-1) - 1.5Z^-2/Z - 0.4Z^-1/(Z-1)On simplification,H(z) = 1-1.5 -0.4Hence the answer is a) 1-1.5 -0.4.