well, f(1) is indicating that x = 1, hmmm for the piecewise, on what section is that?
well, x < 1 is just whenever "x" is less than 1, but not 1.
x ⩾ 1 is whenever "x" is either 1 or greater than 1, so that's our guy, so we use that subfunction to get it.
![f(x)= \begin{cases} 2x&x < 1\\\\ \cfrac{1}{2}x+\cfrac{5}{2}&x\geqslant 1\hspace{3em}\textit{f(1) is in this section} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(1)=\cfrac{1}{2}(1)+\cfrac{5}{2}\implies f(1)=3](https://img.qammunity.org/2024/formulas/mathematics/college/8l989cqkdtiynhtz6qmc2p6u8dbosktor9.png)