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The doubling period of a bacterial population is 10 minutes. At time t = 80 minutes, the bacterial population was 80000.

Find the size of the bacterial population after 5 hours.

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Answer:

After 5 hours, the size of the bacterial population will be 336860180480.

Step-by-step explanation:

Let's solve this problem together. The doubling period of a bacterial population is 10 minutes, which means that every 10 minutes the population doubles in size. After 80 minutes, the population is 80000. We can use this information to find the initial population size.

Let's denote the initial population size as P. Since the population doubles every 10 minutes, after 80 minutes the population will be P * 2^(80/10) = 80000. Solving for P, we get P = 80000 / 2^8 = 312.5.

Now that we know the initial population size, we can find the size of the bacterial population after 5 hours (300 minutes). The population after 300 minutes will be P * 2^(300/10) = 312.5 * 2^30 = 336860180480.

So, after 5 hours, the size of the bacterial population will be 336860180480.

User Alex Kamenkov
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