Question

On a coordinate plane, a line is drawn from point J to point K. Point J is at (negative 3, 1) and point K is at (negative 8, 11).

What is the y-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:3?

y = (StartFraction m Over m + n EndFraction) (y 2 minus y 1) + y 1

–6
–5
5
7

Answer 1

To find the y-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:3, we can use the formula for finding a point given a ratio. The formula is:

y = (m / (m + n)) * (y2 - y1) + y1

In this case, m = 2 and n = 3. Substituting the given coordinates:
y = (2 / (2 + 3)) * (11 - 1) + 1
y = (2/5) * 10 + 1
y = 4 + 1
y = 5

Therefore, the y-coordinate of the point that divides the directed line segment from J to K into a ratio of 2:3 is 5.