To find the value of b when (x+3) is a factor of x^3+bx^2+11x-3, we can use the factor theorem. According to the factor theorem, if (x+3) is a factor of a polynomial, then substituting -3 for x should result in 0.
Let's substitute -3 for x in the given polynomial and set it equal to 0:
(-3)^3 + b(-3)^2 + 11(-3) - 3 = 0
Simplifying the equation:
-27 + 9b - 33 - 3 = 0
Combining like terms:
9b - 63 = 0
Adding 63 to both sides:
9b = 63
Dividing both sides by 9:
b = 7
Therefore, the value of b is 7.

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