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Solve using the quadratic formula
16x^2-8x=-1

2 Answers

3 votes
The answer to your question would be
X= 1/4
User XeniaSis
by
8.1k points
1 vote

Answer:

Explanation:

To solve the quadratic equation 16x^2 - 8x = -1 using the quadratic formula, we need to rearrange the equation in the standard form ax^2 + bx + c = 0.

Given equation: 16x^2 - 8x = -1

We bring all terms to one side to obtain: 16x^2 - 8x + 1 = 0

Comparing this with the standard form ax^2 + bx + c = 0, we have:

a = 16

b = -8

c = 1

The quadratic formula is given by:

x = (-b ± √(b^2 - 4ac)) / (2a)

Substituting the values, we get:

x = (-(-8) ± √((-8)^2 - 4 * 16 * 1)) / (2 * 16)

x = (8 ± √(64 - 64)) / 32

x = (8 ± √0) / 32

Since the discriminant (b^2 - 4ac) is zero, the quadratic equation has only one real root.

x = 8 / 32

x = 1/4

Therefore, the solution to the equation 16x^2 - 8x = -1 is x = 1/4.

User Acvcu
by
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