Final Answer:
You can replace
with an error of magnitude no greater than
for values of x within the range [-1.1, 1.1].
Step-by-step explanation:
The question involves Taylor series and understanding the approximation of
by its Taylor series expansion. The Taylor series expansion for
up to the third-degree term is given by

To determine the range of x values for a given error threshold, we can consider the remainder term in the Taylor series, which is proportional to the fourth derivative of \(\sin(x)\). The remainder term can be expressed using the Lagrange form of the remainder,
, where \(c\) is between \(a\) and \(x\).
For the given error threshold
, we can set up the inequality
and solve for x. In the case of
, the fourth derivative is
, so

Solving the inequality involves finding the maximum absolute value of
within the range [-1,1] and this occurs when
Thus, the range for x is determined by
. leading to
.
