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Suppose that g is a continuous function, 3_∫^5 g(x)dx=18, and

3_∫^10
g(x)dx =36. Find
5_ ∫^10 g(x)dx
those are intergral symbols with numbers on top and bottom. please
show work. thanks

User Pietro M
by
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1 Answer

5 votes

Answer:

18

Explanation:

Given:


\int\limits^3_5 {g(x)} \, dx =18\\\\\int\limits^3_(10) {g(x)} \, dx =36

We have:


\int\limits^3_(10) {g(x)} \, dx = \int\limits^3_(5) {g(x)} \, dx+\int\limits^5_(10) {g(x)} \, dx


\int\limits^5_(10) {g(x)} \, dx = \int\limits^3_(10) {g(x)} \, dx-\int\limits^3_(5) {g(x)} \, dx


\int\limits^5_(10) {g(x)} \, dx = 36-18\\\\=18

User ZacWolf
by
7.7k points

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