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A weather balloon contains 12 L of hydrogen at 740 mm Hg. At what pressure will the volume become 20 L, assuming the temperature and moles remain constant?

1 Answer

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Answer: 444 mmhg

Explanation: to do this problem you need to use the p1v1=p2v2 formula, which is boyle's law.

plug in the values into the equation -> (12)(740)=(20)p2
expand -> 8880=(20)p2
8880/20=p2
444=p2

444 mmhg is the new pressure
if they are asking for pressure in atm make sure to convert mmhg into atm before plugging into the equation!

User Jompper
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