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Solve the simultaneous equations
2x + y = 5
2x2 + y2 = 11

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Answer:

Explanation:

Solve the simultaneous equations 2x + y = 5 2x2 + y2 = 11-example-1
User Sandinmyjoints
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4 votes

Answer:

To solve the given simultaneous equations: 2x + y = 5 ------------(1) 2x^2 + y^2 = 11 ------------(2)

We can use the method of substitution to solve the equations.

Substituting y = 5 - 2x from equation (1) into equation (2), we get: 2x^2 + (5 - 2x)^2 = 112x^2 + 25 - 20x + 4x^2 = 112x^2 + 4x^2 - 20x + 25 - 11 =

simplifying, we get: 6x^2 - 20x + 14 = 0

Dividing by 2, we get: 3x^2 - 10x + 7 = 0

Factorizing, we get: (3x - 7)(x - 1) = 0

Solving for x, we get: x = 1 or x = 7/3

Now substituting x = 1 in equation (1), we get:2(1) + y = 5y = 5 - 2y = 3 Therefore, one solution is x = 1 and y = 3

Substituting x = 7/3 in equation (1), we get: 2(7/3) + y = 5y = 5 - 14/3y = 1/3

Therefore, the other solution is x = 7/3 and y = 1/3

Hence, the solutions of the given simultaneous equations are x = 1 and y = 3 or x = 7/3 and y = 1/3.

Explanation:

Hope this helped!! Have a great day/night!!

User John Kloian
by
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