Answer:
AI-generated answer
Given that the balanced equation for the reaction between NaHCO3 and C6H8O7 is as follows:
3NaCO3(aq) + C6H8O7(aq) → 3CO2(g) + 3H2O(l) + Na3C6H5O7(aq)We need to find out the number of moles of CO2 and Na3C6H5O7 produced when 13.5 mol of NaHCO3 and 4.5 mol of C6H8O7 react.
To balance the given equation, it is important to make sure that the number of atoms on the reactant side is equal to the number of atoms on the product side. Since we have three Na atoms on the reactant side, we need to multiply the Na3C6H5O7 by 3. The balanced equation now becomes: 3NaHCO3(aq) + C6H8O7(aq) → 3CO2(g) + 3H2O(l) + Na3C6H5O7(aq)Now we can calculate the moles of CO2 produced by using mole ratio of NaHCO3 to CO2 from the balanced equation which is 3:3 or 1:1. Hence, moles of CO2 produced is also 13.5 mol.
The moles of Na3C6H5O7 produced are calculated using the mole ratio of C6H8O7 to Na3C6H5O7 from the balanced equation which is 1:1. Hence, the moles of Na3C6H5O7 produced is 4.5 mol.
Therefore, 13.5 moles of CO2 and 4.5 moles of Na3C6H5O7 will be produced.
Step-by-step explanation:
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