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How do you get 80 after multiplying these together? (8-4i)x(8+4i)

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Answer/Step-by-step explanation:

There are four multiplications you have to do to times these together.

If you have learned how to multiply something like this:

(x + 3)(x - 3)

it will be done in the same way.

(Actually, also there's a short cut called Difference of Two Squares or Difference of Perfect Squares)

Here are the

four multiplications:

8×8 = 64

8 × 4i = 32i

-4i × 8 = -32i

-4i × 4i = -16i^2

Some people use an area model to multiply these or algorithm called FOIL.

So, the two middle multiplications add up to zero and just like, zero out each other 32i + -32i is just nothing, zero.

Then you are left with the first and last terms.

64 + (-16i^2)

REMEMBER:

i^2 = -1

64 + (-16)(-1)

= 64 + 16

= 80

User Yahia Zakaria
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