Answer:
Explanation:
"To show that the square will fit inside the circle without touching the edge of the circle, we need to find the diameter of the circle, which is also the diagonal of the square.
The diagonal of a square with side length 5 cm is:
d = √(5² + 5²) = √50 ≈ 7.07 cm
The diameter of the circle is equal to the diagonal of the square, so the diameter of the circle is also approximately 7.07 cm. The radius of the circle is half the diameter, so the radius of the circle is approximately:
r = d / 2 ≈ 3.54 cm
The side length of the square is 5 cm, which is less than the radius of the circle. Therefore, the square will fit inside the circle without touching the edge of the circle. Does that help?"