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Solve for the value of x using the quadratic formula

22 POINTS Solve for the value of x using the quadratic formula-example-1

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Answer:

To solve the quadratic equation 3x^2 + 3x - 18 = 0 using the quadratic formula, we need to identify the coefficients a, b, and c in the general form of a quadratic equation, ax^2 + bx + c = 0.

In this case:

a = 3

b = 3

c = -18

Now we can substitute these values into the quadratic formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

Plugging in the values:

x = (-(3) ± √((3)^2 - 4(3)(-18))) / (2(3))

Simplifying further:

x = (-3 ± √(9 + 216)) / 6

x = (-3 ± √225) / 6

Now, let's calculate the two possible solutions:

x1 = (-3 + √225) / 6

x2 = (-3 - √225) / 6

Calculating the square root of 225:

x1 = (-3 + 15) / 6 = 12 / 6 = 2

x2 = (-3 - 15) / 6 = -18 / 6 = -3

Therefore, the solutions to the quadratic equation 3x^2 + 3x - 18 = 0 are:

x1 = 2

x2 = -3

User Elhoim
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