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Find the equation of the line shown.

Find the equation of the line shown.-example-1

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to get the equation of any straight line, we simply need two points off of it, let's use those two in the picture below.


(\stackrel{x_1}{-4}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{1}-\stackrel{y1}{3}}}{\underset{\textit{\large run}} {\underset{x_2}{4}-\underset{x_1}{(-4)}}} \implies \cfrac{-2}{4 +4} \implies \cfrac{ -2 }{ 8 } \implies - \cfrac{1}{4}


\begin{array}ll \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{3}=\stackrel{m}{- \cfrac{1}{4}}(x-\stackrel{x_1}{(-4)}) \implies y -3 = - \cfrac{1}{4} ( x +4) \\\\\\ y-3=- \cfrac{1}{4}x-1\implies {\Large \begin{array}{llll} y=- \cfrac{1}{4}x+2 \end{array}}

Find the equation of the line shown.-example-1
User Icedwater
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