Question

What mass would occupied by 120 mole of argon gas at stp

Answer 1

mass=8,640g

Step-by-step explanation:

`n = (mass)/(molar \: mass)`

where

mole(n)= 120mol

Molar mass = Ar2

= 36×2

= 72g/mol.

Mass = ?

Therefore mass =

`120 = (m)/(72) . \\ 120 * 72 = m \\ 8640g = m`