90.7k views
4 votes
Write the sequence of natural numbers which leaves the remainder 3 on dividing by 5

User Kuromoka
by
7.7k points

1 Answer

3 votes

Answer: 3, 8, 13, 18, 23, etc...

Explanation:

To get a remainder of 3 upon dividing by 5, we must get multiples of 5 then add 3 to each. So, we start with 0+3=3, then 5+3=8, 10+3=13, etc... So, we end up with the sequence 3, 8, 13, 18, 23... notice how each term is 5 more than the previous.

User Sharrone
by
8.7k points

No related questions found