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Write the sequence of natural numbers which leaves the remainder 3 on dividing by 5

User Kuromoka
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Answer: 3, 8, 13, 18, 23, etc...

Explanation:

To get a remainder of 3 upon dividing by 5, we must get multiples of 5 then add 3 to each. So, we start with 0+3=3, then 5+3=8, 10+3=13, etc... So, we end up with the sequence 3, 8, 13, 18, 23... notice how each term is 5 more than the previous.

User Sharrone
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