Question

37 points if someone gets it right

You spin a spinner that is equally divided into 4 parts. 1 part is white, 1 part is blue and 2 parts are black. After that, you roll a six-sided die one time.

What is the probabilityof the spinner stopping a a blue section then rolling a 1

Answer 1

1 / 24, or 4.16667%

Explanation:

To find the probability of both events happening you first need to calculate the probability of each event, then multiply them together.

The blue section is 1 of 4 total sections, meaning the probability is \frac{1}{4}

A six sided die has 1 of 6 possible outcomes, or \frac{1}{6}

`(1)/(4) * (1)/(6) = (1)/(24)`