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A line L, passing through the points 6 -13 is parallel to the line which passes through 7 4 and -3 9 find the equation of the line L​

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To determine the equation of the line parallel to another line passing through a given point, we need to use the slope of the given line.

Given Points:

Point A: (6, -13)

Point B: (7, 4)

Point C: (-3, 9)

First, let's calculate the slope of the line passing through points B and C using the slope formula:

Slope (m) = (y2 - y1) / (x2 - x1)

m = (4 - 9) / (7 - (-3))

= (-5) / (7 + 3)

= -5/10

= -1/2

Since the line L is parallel to the line passing through points B and C, it will have the same slope (-1/2).

Now, we can use the point-slope form of a linear equation to find the equation of line L:

y - y1 = m(x - x1)

Using point A (6, -13) and the slope (-1/2):

y - (-13) = (-1/2)(x - 6)

y + 13 = (-1/2)x + 3

y = (-1/2)x - 10

Therefore, the equation of the line L passing through point (6, -13) and parallel to the line passing through (7, 4) and (-3, 9) is y = (-1/2)x - 10.

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