Answer:

Explanation:
We can write the equation of the line we are trying to solve for in point-slope form, then convert it to slope-intercept form.
Point-slope form is:

where
is the line's slope and
is a point on the line.
We are given in the problem that
is a point on the line, so we can identify the following variables to plug into point-slope form:
We know that a slope that is perpendicular to a given slope is its negative reciprocal. In equation form:

We can find this for
:

↓ skip, flip, and multiply


Now that we have
,
, and
, we can find an equation for the line perpendicular to
that goes through
by plugging these values into the point-slope form equation:


Finally, we can convert this to slope-intercept form by isolating
.

↓ apply the distributive property to the right side ...


↓ add 1 to both sides
