Question

100 points if someone gets it right.

You randomly draw a marble, put it back, and randomly draw another marble.

2 striped marbles 3 checkered marbles, 4 black marbles.

What is the probability of drawing a striped marble and then drawing a striped marble? Write your answer as a fraction

Answer 1

4/81

Explanation:

The probability of drawing a striped marble on the first draw is 2/9 because there are a total of 9 marbles and 2 of them are striped.

Since the marble is put back, the probability of drawing a striped marble on the second draw is still 2/9.

To find the probability of both events happening, we multiply their probabilities:

P(striped, then striped) = P(striped on first draw) × P(striped on second draw)

P(striped, then striped) = (2/9) × (2/9) = 4/81

Therefore, the probability of drawing a striped marble and then drawing a striped marble is 4/81.

If this answer is not you want, you can provide a formula for more accurate answer.

Answer 2

Answer: 4/81

Explanation:

2 striped

3 checkered

4 black

9 total

First time:

P(striped) = 2/9 >There are 2 out of 9 total

Second:

P(striped) = 2/9 >You put the marble back

Because the statement says "AND THEN" it is dependent on first so multiply the 2 probabilities

P(striped AND striped) = (2/9)(2/9)

P(striped AND striped) = 4/81