The solutions of the original equation on the interval: [0, 2π) is:
Option (A): π/6, 5π/6
The solutions of the original equation on the interval are:
[0, 2π) is: Option (A): π/6, 5π/6
- Multiply both sides by 2:
2(1 - cos θ) = 2( 2 - √3 / 2)
2 - 2 cos θ = 2 - √3
- Add: 2 cos θ to both sides:
2 = 2 cos θ + √3
- Subtract 2 from both sides:
0 = 2 cos θ + √3 - 2
2 = 2 cos θ + √3
- Subtract √3 from both sides:
2 - √3 = 2 cos θ
2 - √3/2 = cos θ
θ = arcos(2 - √3/2)
θ = π/6, 5π/6
The solutions of the original equation on the interval are:
[0, 2π) is: Option (A): π/6, 5π/6
Hope it helps!