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Solve on the interval [0,2pi): 1-costheta=2-square3/2

Solve on the interval [0,2pi): 1-costheta=2-square3/2-example-1
User DaveAlden
by
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1 Answer

7 votes
  • Answer:

The solutions of the original equation on the interval: [0, 2π) is:

Option (A): π/6, 5π/6

  • Explanation:

The solutions of the original equation on the interval are:

[0, 2π) is: Option (A): π/6, 5π/6

  • Multiply both sides by 2:

2(1 - cos θ) = 2( 2 - √3 / 2)

  • Simplify:

2 - 2 cos θ = 2 - √3

  • Add: 2 cos θ to both sides:

2 = 2 cos θ + √3

  • Subtract 2 from both sides:

0 = 2 cos θ + √3 - 2

  • Add 2 to both sides:

2 = 2 cos θ + √3

  • Subtract √3 from both sides:

2 - √3 = 2 cos θ

  • Divide both sides by 2:

2 - √3/2 = cos θ

  • Find the angles:

θ = arcos(2 - √3/2)

  • Calculate the angles:

θ = π/6, 5π/6

  • Draw a conclusion:

The solutions of the original equation on the interval are:

[0, 2π) is: Option (A): π/6, 5π/6

Hope it helps!

User Le Droid
by
8.0k points

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