Question

A carnival game has a bowl with 50 packages with one item in each: 25 are marbles, 10 or pieces of gum, and the breast contain a new nickel. If each marble is worth two cents, and the pieces of gum are each worth a dime, what is the expected value of a random choice from the bowl?

Answer 1

Explanation:

According to the information you provided, there are 25 marbles, 10 pieces of gum, and 15 new nickels in the bowl. The probability of getting a marble is 1/2, the probability of getting a piece of gum is 1/5, and the probability of getting a new nickel is 3/10 .

Each marble is worth 2 cents and each piece of gum is worth 10 cents. To calculate the expected value of a random choice from the bowl, we need to multiply the probability of each item by its value and sum them up:

Expected value = (1/2 * 2 cents) + (1/5 * 10 cents) + (3/10 * 5 cents) Expected value = (1 cent) + (2 cents) + (1.5 cents) Expected value = 4.5 cents

Therefore, the expected value of a random choice from the bowl is 4.5 cents .

I hope this helps!